'(("1" nil "France")("2" nil "Germany")("3" nil "Holland")("D" nil "Berne"))
Is there a very easy and quick way to get the string to following?"France(1)/Germany(2)/Holland(3)/Berne(D)/"
Or"France(1)/Germany(2)/Holland(3)/Berne(D)"
(strcat (caddar lst) "(" (caar lst) ")"
(apply (function strcat) (mapcar (function (lambda (l) (strcat "/" (caddr l) "(" (car l) ")"))) (cdr lst))))
-> "France(1)/Germany(2)/Holland(3)/Berne(D)"
(vl-string-right-trim
"/"
(apply 'strcat
(mapcar '(lambda (x) (strcat (last x) "(" (car x) ")/"))
'(("1" nil "France") ("2" nil "Germany") ("3" nil "Holland") ("D" nil "Berne"))
)
)
)