I am clueless as how to use vl-remove-if vl-member, etc. I would like to know how to filter a list based on an item. For instance. If the list contains "test" I want to remove it from the list and return a list without it.
(setq lst (list '("1" "2" "3" "test") '("a" "b" "c" "finished") '("a" "b" "c" "test")))
desired result to filter out "test"
_$ lst
(("a" "b" "c" "finished"))
desired result to filter out "finished"
_$ lst
(("1" "2" "3" "test")("a" "b" "c" "test"))