Topic: Help with vla-get-startpoint

[ozimad]

Hi can somebody helpme with getting startpoint:

Command: ; error: bad argument type: VLA-OBJECT 2127010984 - this is the error

    (setq temp (ssget "l")) ;;;iselect blocj
    (command "_.explode" temp) ;;;i explode it
    (setq temp1 (entlast)) ;;get the line out of block
    (setq objid1 (vla-get-objectid (vlax-ename->vla-object temp1)))
    (setq stpt (vlax-SafeArray->List (vlax-Variant-Value (vla-Get-StartPoint objid1))))
    (print stpt)
    (command "_.erase" temp1 "")

many thanks!

[gile]

Hi,

The argument requiered by vla-get-StartPoint have to be a vla-object type, not an ObjectId

[Lee Mac]

Also, you can avoid dealing with variants by using:

Code: [Select]

(vlax-get obj 'StartPoint)

 

[CAB]

One more:

Code: [Select]

(vlax-curve-getstartpoint curve-obj)

[T.Willey]

More cat skinning ( just 'cuz I was in the mood )  :ugly:

Code: [Select]

(
    (lambda ( x )
        (vlax-curve-getPointAtParam
            x
            (vlax-curve-getStartParam x)
        )
    )
    (car (entsel))
)


[Lee Mac]

Curve functions are the way to go - much quicker with Enames and no need to convert to vla-object...