TheSwamp
CAD Forums => Vertically Challenged => Topic started by: ekoneo on August 25, 2014, 03:02:13 AM
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Is there any way to define symmetrical of a superelevation that defined with a vertical target?
I have a small road project. It has a profile including a superelevation definitions.
The problem is the intersection region with another road. Because left side is targetted to a main road's edge. So the left side has a slope value.
I need to define symmetric slope (negative signed) to the rigth side of my assembly.
Is this possible?
For instance:
at a 0+100 station if left lane slope is +1.23%, right lane slope must be -1.23%.
at a 0+110 station if left lane slope is +1.17%, right lane slope must be -1.17%.
at a 0+120 station if left lane slope is +1.10%, right lane slope must be -1.10%.
etc..
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you can use a helper corridor to extract surface/profile from to use in your assembly targeting parameters
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Thanks. I did what I need by preparing a helper corridor as mjfarrell.
But preparation of a helper corridor difficult and complex and boring :(
I have to work 2 times more for each corridor.
I wish there was a way to assign a value to a subbassembly from another subbassembly like a paramater.
LeftSideSuperelevation= -1*RihtSideSuperelevation
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Thanks. I did what I need by preparing a helper corridor as mjfarrell.
But preparation of a helper corridor difficult and complex and boring :(
I have to work 2 times more for each corridor.
I wish there was a way to assign a value to a subbassembly from another subbassembly like a paramater.
LeftSideSuperelevation= -1*RihtSideSuperelevation
There is;
Take note of the USE button in the assembly parameters box
however this can be an interesting challenge to do as well without good naming convention and insertion order of your sub assembly components.